Reply To: Interview experience

#24735
supanshah
Participant

    sushantgupta wrote:

    Because the prob. of A dying does not depends on the death of B and vice- versa. Therefore intersection of the two prob. will be 0.

    On the other hand in option 2 , we will add the individual prob. of A dying and B dying .

    Thus in option 1 , I think the prob. will be 0 and in option 2 , we might get some prob. which will be greater than 0.

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    All correct, except the probability of option 1 will “almost be zero” as both the probabilities would be multiplied. P(A&B)=P(A)*P(B) for independent events. This would definitely be close to zero, but asserting it is zero is false.

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